Aromatisation of n -heptane by passing over ( Al 2 O 3 + Cr 2 O 3 ) catalyst at 773 K gives, Benzene, Toluene, Mixture of both, Heptylene

Aromatisation of n -heptane by passing over ( Al 2 O 3 + Cr 2 O 3 ) catalyst at 773 K gives

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Aromatisation of $n$-heptane by passing over $\left(\mathrm{Al}_2 \mathrm{O}_3+\mathrm{Cr}_2 \mathrm{O}_3\right)$ catalyst at $773 \mathrm{~K}$ gives

ChemistryHydrocarbonsJEE Main

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Solution:

2299 Upvotes Verified Answer

The correct answer is: Toluene

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