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Arrange stability of the given carbon cation in decreasing order
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Verified Answer
The correct answer is:
(iii) $>($ ii $)>($ i $)>($ iv $)$
The correct decreasing order of the stabilities of given carbocations is
$$
\text { (iii })>(\text { ii })>(\text { i })>(\text { iv })
$$
Because electron releasing effect stabilises the carbocation. Electron releasing order is
$$
\mathrm{NH}_{2}>\mathrm{OH}>\mathrm{OCH}_{3}>\mathrm{Cl} \text {. }
$$
$$
\text { (iii })>(\text { ii })>(\text { i })>(\text { iv })
$$
Because electron releasing effect stabilises the carbocation. Electron releasing order is
$$
\mathrm{NH}_{2}>\mathrm{OH}>\mathrm{OCH}_{3}>\mathrm{Cl} \text {. }
$$
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