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Arrange the following alcohols in order of increasing reactivity towards sodium metal.
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The correct answer is:
(i) < (ii) < (iii)
More the number of methyl groups (electron releasing) lesser will be the acidity. Hence the reactivity order towards sodium metal will be as follows
tertiary (i) < secondary (ii) < primary (iii).
tertiary (i) < secondary (ii) < primary (iii).
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