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Question: Answered & Verified by Expert
Arrange the following alkyl halides in order of dehydrohalogenation; C2H5I,C2H5Cl,C2H5Br,C2H5F
ChemistryHaloalkanes and HaloarenesNEET
Options:
  • A C2H5F>C2H5Cl>C2H5Br>C2H5I
  • B C2H5I>C2H5Br>C2H5Cl>C2H5F
  • C C2H5I>C2H5Cl>C2H5Br>C2H5F
  • D C2H5F>C2H5I>C2H5Br>C2H5Cl
Solution:
2249 Upvotes Verified Answer
The correct answer is: C2H5I>C2H5Br>C2H5Cl>C2H5F
As with the increase in size X- bond length increases but bond strength decreases so reactivity increases. As size increases as F-<Cl-<Br-<I- .
Hence reactivity order is C2H5I>C2H5Br>C2H5Cl>C2H5F

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