Search any question & find its solution
Question:
Answered & Verified by Expert
Arrange the following complexes in the increasing order of conductivity of their solution $\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2$
Solution:
1683 Upvotes
Verified Answer
Ions or molecules present outside the coordination sphere are ionisable. A complex which gives more ions on dissolution, is more conducting. As the number of ions increases, conductivity increases in the order given below:
$$
\begin{aligned}
&\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right], < \left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right] \mathrm{Cl} < \\
&\text { (1 ion) (2 ions) }\\
&\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2 < \left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_3\\
&\text { (3 ions) }\\
&\text { (4 ions) }
\end{aligned}
$$
$$
\begin{aligned}
&\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right], < \left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right] \mathrm{Cl} < \\
&\text { (1 ion) (2 ions) }\\
&\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2 < \left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_3\\
&\text { (3 ions) }\\
&\text { (4 ions) }
\end{aligned}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.