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Question: Answered & Verified by Expert
Arrange the following polymers in increasing order of their intermolecular forces.
Nylon-6, 6, buna-S, polythene, neoprene
ChemistryPolymersJIPMERJIPMER 2018
Options:
  • A Neoprene $ \lt $ buna-S $ \lt $ nylon-6, $6, \lt $ polythene
  • B Neoprene $ \lt $ buna-S $ \lt $ polythene $ \lt $ nylon-6, 6
  • C Polythene $ \lt $ nylon- $6,6 \lt $ buna- $\mathrm{S} \lt $ neoprene
  • D Polythene $ \lt $ buna-S $ \lt $ nylon-6, $6 \lt $ neoprene
Solution:
1860 Upvotes Verified Answer
The correct answer is: Neoprene $ \lt $ buna-S $ \lt $ polythene $ \lt $ nylon-6, 6
The increasing order of intermolecular forces in different polymers is elastomers < plastics $ \lt $ fibres. So, in order to solve such problem, first classify the given polymer into the above classes and then arrange them in increasing order of forces. Neoprene (synthetic rubber) is an elastomer, buna-S is also an elastomer, polythene is plastic and nylon-6, 6 is a fibre. So, the increasing order of intermolecular forces of the given polymer is
Neoprene $ \lt $ buna-S $ \lt $ polythene $ \lt $ nylon- 6,6

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