$\mathrm{N}{\mathrm{H}}_4\mathrm{C}\mathrm{l}$ undergoes cationic hydrolysis hence $\mathrm{p}\mathrm{H}$ is $<7$ because the solution due to cationic hydrolysis in acids.
$\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{N}$ undergoes anionic hydrolysis hence $\mathrm{p}\mathrm{H}$ is $>7$ .
$\mathrm{H}\mathrm{C}\mathrm{l}$ is strong acid and $\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{l}$ is neutral solution.
Hence the $\mathrm{p}\mathrm{H}$ of given solutions will increases.
$\mathrm{H}\mathrm{C}\mathrm{l}<\mathrm{N}{\mathrm{H}}_4\mathrm{C}\mathrm{l}<\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{l}<\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{N}$