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Arrange the following species in the decreasing order of their bond orders:
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The correct answer is:
(II) $>$ (I) $>$ (III)
( The strength of bond is determined by bond order (BO).
Number of electrons in bonding molecular orbital (a) - Number of electrons in
$$
\mathrm{BO}=\frac{\text { antibonding molecular orbital }(b)}{2}
$$
Number of electrons in bonding molecular orbital (a) - Number of electrons in
$$
\mathrm{BO}=\frac{\text { antibonding molecular orbital }(b)}{2}
$$
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