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Arrange the hydrides of group 15 in correct decreasing order of reducing nature.
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The correct answer is:
$\mathrm{BiH}_{3}>\mathrm{SbH}_{3}>\mathrm{AsH}_{3}>\mathrm{PH}_{3}>\mathrm{NH}_{3}$
Trihydrides of group 15 elements are given on the basis of reducing character as follows:
$$
\mathrm{BiH}_{3}>\mathrm{SbH}_{3}>\mathrm{AsH}_{3}>\mathrm{PH}_{3}>\mathrm{NH}_{3}
$$
The reducing character increases down the group because the bond strength of $E-H$ bond decreases. As the size of element $E$ down the group increases and thus, the bond dissociation energy decreases. This facilitates the dissociation of hydrogen atoms and hence, down the group, the reducing character increase.
$$
\mathrm{BiH}_{3}>\mathrm{SbH}_{3}>\mathrm{AsH}_{3}>\mathrm{PH}_{3}>\mathrm{NH}_{3}
$$
The reducing character increases down the group because the bond strength of $E-H$ bond decreases. As the size of element $E$ down the group increases and thus, the bond dissociation energy decreases. This facilitates the dissociation of hydrogen atoms and hence, down the group, the reducing character increase.
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