As O 2 (l) is cooled at 1 atm pressure, it freezes to form solid I at 54.5 K. At a lower temperature, solid I rearrange to solid II, which has a different crystal structure. Thermal measurements show that for the phase transition solid I to slid II, Δ H = - 743.1 J m o l - 1 and Δ S = - 17.0 J K - 1 m o l - 1 . At what temperature are solids I and II in equilibrium?

Question

As O 2 (l) is cooled at 1 atm pressure, it freezes to form solid I at 54.5 K. At a lower temperature, solid I rearrange to solid II, which has a different crystal structure. Thermal measurements show that for the phase transition solid I to slid II, Δ H = - 743.1 J m o l - 1 and Δ S = - 17.0 J K - 1 m o l - 1 . At what temperature are solids I and II in equilibrium?, 2.06 K, 31.6 K, 43.7 K, 53.4 K

MARKS App · Accepted Answer

Since, Δ G = Δ H - T Δ S At equilibrium Δ G = 0 ∴ Δ H = T Δ S Given Δ H = - 743.1 J / m o l Δ S = - 17.0 J K - 1 m o l - 1 ∴ - 743.1 - 17.0 = T T = 43.7 K At this temperature solid, I and II are in equilibrium.

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