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As shown in figure the tension in the horizontal cord is $30 \mathrm{~N}$. The weight $W$ and tension in the string $O A$ in Newton are
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Verified Answer
The correct answer is:
$30 \sqrt{3}, 60$
From the figure $T \sin 30^{\circ}=30$...(i)
$T \cos 30^{\circ}=W$...(ii)
By solving equation (i) and (ii) we get
$W=30 \sqrt{3} N$ and $T=60 N$
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