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Assertion (A) $f(x)=|x|$ is differentiable at $x=a \neq 0$ and continuous but not differentiable at $x=0$
Reason (R) If a function is differentiable at a point, then it is continuous at the point. But converse is not true.
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Reason (R) If a function is differentiable at a point, then it is continuous at the point. But converse is not true.
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$\mathrm{A}$ is correct, $\mathrm{R}$ is correct, $\mathrm{R}$ is correct explanation of $\mathrm{A}$
From the graph of $f(x)=|x|$, it is clear that $f(x)$ is everywhere continuous but not differentiable at $x=0$, due to sharp edge.
$\therefore f(x)=|x|$ is differentiable if $x \in R-\{0\}$.
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