Search any question & find its solution
Question:
Answered & Verified by Expert
Assertion (A) Ferricyanide ion oxidises $\mathrm{H}_2 \mathrm{O}_2$ to $\mathrm{H}_2 \mathrm{O}$ in basic medium.
Reason (R) Oxidation product of $\mathrm{H}_2 \mathrm{O}_2$ is $\mathrm{O}_2$. Which of the following is true?
Options:
Reason (R) Oxidation product of $\mathrm{H}_2 \mathrm{O}_2$ is $\mathrm{O}_2$. Which of the following is true?
Solution:
1047 Upvotes
Verified Answer
The correct answer is:
(A) is false, but (R) is true
In basic medium $\mathrm{H}_2 \mathrm{O}_2$ reacts as :
$$
\mathrm{H}_2 \mathrm{O}_2+2 \mathrm{OH}^{-} \longrightarrow 2 \mathrm{H}_2 \mathrm{O}+\mathrm{O}_2+2 e^{-}
$$
In alkaline medium $\mathrm{H}_2 \mathrm{O}_2$ reduces ferricyanide to ferrouscyanide as follows:
$$
\mathrm{H}_2 \mathrm{O}_2+2 \mathrm{OH}^{-} \longrightarrow 2 \mathrm{H}_2 \mathrm{O}+\mathrm{O}_2+2 e^{-}
$$
In alkaline medium $\mathrm{H}_2 \mathrm{O}_2$ reduces ferricyanide to ferrouscyanide as follows:
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.