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Question: Answered & Verified by Expert
Assertion (A) : $\mathrm{NaCl}$ is less soluble in heavy water than in ordinary water.

Reason (R) : Dielectric constant of ordinary water is more than that of heavy water.
The correct answer is
ChemistryHydrogenAP EAMCETAP EAMCET 2007
Options:
  • A Both (A) and (R) are true and (R) is the correct explanation of (A)
  • B Both $(\mathrm{A})$ and $(\mathrm{R})$ are true but $(\mathrm{R})$ is not the correct explanation of (A)
  • C (A) is true, but (R) is not true
  • D (A) is not true, but (R) is true
Solution:
2920 Upvotes Verified Answer
The correct answer is: Both (A) and (R) are true and (R) is the correct explanation of (A)
$\mathrm{NaCl}$ is less soluble in heavy water than in ordinary water because dielectric constant of ordinary water $(i e, 81)$ is more than that of heavy water (ie, 80).

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