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Assertion (A) : $\mathrm{NaCl}$ is less soluble in heavy water than in ordinary water.
Reason (R) : Dielectric constant of ordinary water is more than that of heavy water.
The correct answer is
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Reason (R) : Dielectric constant of ordinary water is more than that of heavy water.
The correct answer is
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The correct answer is:
Both (A) and (R) are true and (R) is the correct explanation of (A)
$\mathrm{NaCl}$ is less soluble in heavy water than in ordinary water because dielectric constant of ordinary water $(i e, 81)$ is more than that of heavy water (ie, 80).
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