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Assertion (A)Variance of $4 x_1, 4 x_2, \ldots, 4 x_n$ is 16 times the variance of $x_1, x_2, x_3, \ldots, x_n$Reason (R) If $y=a x+b$, then variance of $y$ is a (variance of $x)+b$
The correct option among the following is
Options:
The correct option among the following is
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The correct answer is:
(A) is true but $(R)$ is false.
Let variance of $x_1, x_2, x_3, \ldots, x_n$ be $\sigma^2$, then variance of $4 x_1, 4 x_2, \ldots, 4 x_n$ is $4^2 \sigma^2$ is $16 \sigma^2$
And variance dependent on change of scale.
And variance dependent on change of scale.
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