Search any question & find its solution
Question:
Answered & Verified by Expert
Assertion : According to transition state theory, for the formation of an activated complex, one of the vibrational degrees of freedom is converted into a translational degree of freedom.
Reason : Energy of the activated complex is higher than the energy of reactant molecules.
Options:
Reason : Energy of the activated complex is higher than the energy of reactant molecules.
Solution:
2412 Upvotes
Verified Answer
The correct answer is:
If both assertion and reason are true and reason is the correct explanation of the assertion
$: A+B \rightleftharpoons(A B)^{\#} \rightarrow$ products.
The activated complex can also be treated as a distinct chemical species in equilibrium with the reactants which then decompose into products. It is, however, a special molecule in which one vibrational degree of freedom has been converted to a translational degree of freedom along the reaction coordinate. It must be remembered that the activated complex is not merely an intermediate in process of breaking or forming of chemical bonds. It is unstable because it is situated at the maximum of the potential energy barrier separating the produts from the reactants. The difference between the energy of the activated complex $\left(E_1\right)$ and the energy of the reactants $\left(E_2\right)$ is the activation energy, $E_a$.
$$
E_1-E_2=E_a, E_1>>E_2 .
$$
The activated complex can also be treated as a distinct chemical species in equilibrium with the reactants which then decompose into products. It is, however, a special molecule in which one vibrational degree of freedom has been converted to a translational degree of freedom along the reaction coordinate. It must be remembered that the activated complex is not merely an intermediate in process of breaking or forming of chemical bonds. It is unstable because it is situated at the maximum of the potential energy barrier separating the produts from the reactants. The difference between the energy of the activated complex $\left(E_1\right)$ and the energy of the reactants $\left(E_2\right)$ is the activation energy, $E_a$.
$$
E_1-E_2=E_a, E_1>>E_2 .
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.