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Assertion : As work function of a material increases by some mechanism, it requires greater energy to excite the electrons from its surface.
Reason : A plot of stopping potential $\left(V_s\right)$ versus frequency (v) for different metals, has greater slope for metals with greater work functions.
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Reason : A plot of stopping potential $\left(V_s\right)$ versus frequency (v) for different metals, has greater slope for metals with greater work functions.
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The correct answer is:
If assertion is true but reason is false.
As eV $=h \mathrm{~s}-W$
$V_{\mathrm{s}}=\left(\frac{h}{e}\right) \mathrm{v}-\left(\frac{W}{e}\right)$
For $V_{\mathrm{s}}$ versus $v$ graph, slope $=\frac{h}{e}=$ constant.
$V_{\mathrm{s}}=\left(\frac{h}{e}\right) \mathrm{v}-\left(\frac{W}{e}\right)$
For $V_{\mathrm{s}}$ versus $v$ graph, slope $=\frac{h}{e}=$ constant.
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