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Assertion : $\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}$ has $d^2 s p^3$ type hybridisation.
Reason: $\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}$ ion shows magnetic moment corresponding to two unpaired electrons.
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Reason: $\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}$ ion shows magnetic moment corresponding to two unpaired electrons.
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The correct answer is:
If assertion is true but reason is false.
$\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}$ ion shows magnetic moment corresponding to one unpaired electron.
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