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Assertion : For Balmer series of hydrogen spectrum, the value $n_1=2$ and $n_2=3,4,5 \ldots$.
Reason : The value of $n_2$ for a line in Balmer series of hydrogen spectrum having the highest wavelength is 6 .
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Reason : The value of $n_2$ for a line in Balmer series of hydrogen spectrum having the highest wavelength is 6 .
Solution:
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The correct answer is:
If assertion is true but reason is false.
The wavelength of the line can be calculated by the Rydberg formula :
$$
\frac{1}{\lambda}=R\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right), R=\text { Rydberg constant }
$$
Therefore, wavelength will be highest in Balmer series $\left(n_1=2\right.$ ) when $n_2$ is 3 .
$$
\frac{1}{\lambda}=R\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right), R=\text { Rydberg constant }
$$
Therefore, wavelength will be highest in Balmer series $\left(n_1=2\right.$ ) when $n_2$ is 3 .
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