Search any question & find its solution
Question:
Answered & Verified by Expert
Assertion : For Balmer series of hydrogen spectrum, the value $n_1=2$ and $n_2=3,4,5$.
Reason: The value of $n$ for a line in Balmer series of hydrogen spectrum having the highest wavelength is 4 and 6 .
Options:
Reason: The value of $n$ for a line in Balmer series of hydrogen spectrum having the highest wavelength is 4 and 6 .
Solution:
1925 Upvotes
Verified Answer
The correct answer is:
If the assertion is true but the reason is false.
The wavelength of the line can be calculated by the Ritz formula :
$$
\frac{1}{\lambda}=R\left(\frac{1}{n_1^2}-\frac{1}{n_2{ }^2}\right), R=\text { Rydberg constant }
$$
Therefore, for calculating highest wavelength in Balmer series $\left(n_1=2\right), n_2$ should be 3 .
$$
\frac{1}{\lambda}=R\left(\frac{1}{n_1^2}-\frac{1}{n_2{ }^2}\right), R=\text { Rydberg constant }
$$
Therefore, for calculating highest wavelength in Balmer series $\left(n_1=2\right), n_2$ should be 3 .
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.