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Question: Answered & Verified by Expert
Assertion: If a wire is stretched, only half of the work done in stretching the wire remains stored as elastic potential energy.
Reason: Potential energy stored in the wire is \( \frac{1}{2} \) (stress) \( \times \) (strain).
PhysicsMechanical Properties of SolidsJEE Main
Options:
  • A Both Assertion and Reason are true and Reason is the correct explanation of Assertion.
  • B Both Assertion and Reason are true but Reason is not the correct explanation of Assertion.
  • C If Assertion is true but Reason is false.
  • D If Assertion is false but Reason is true.
Solution:
2255 Upvotes Verified Answer
The correct answer is: If Assertion is true but Reason is false.

Potential energy,  

U=12stress×strain×volume

  U=12FAllAl

  U=12Fl ,

Work done,

W=F×displacement

  W=F×l ,

So, half of the work done in stretching the wire remains stored as elastic potential energy.

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