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Assertion: If an electron and proton possessing same kinetic energy enter an electric field in a perpendicular direction, the path of the electron is more curved than that of the proton.
Reason: Electron forms a larger curve due to its small mass.
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Reason: Electron forms a larger curve due to its small mass.
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The correct answer is:
If both assertion and reason are false.
As $q E=\frac{m v^2}{r}, r=\frac{m v^2}{q E}=\frac{2 K}{q E} \quad\left(\right.$ where $\left.K=\frac{1}{2} m v^2\right)$
i.e., $r \propto \frac{1}{q}$.
Since electron and proton have equal charge, $r$ is the same for both of them.
Here, $r$ depends on $K$ (which is given to be the same for both the particles) and as such not on their masses.
i.e., $r \propto \frac{1}{q}$.
Since electron and proton have equal charge, $r$ is the same for both of them.
Here, $r$ depends on $K$ (which is given to be the same for both the particles) and as such not on their masses.
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