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Question: Answered & Verified by Expert
Assume that an electric field $\mathrm{E}=30 \mathrm{x}^2 \mathrm{i}$ exists in space. If ' $\mathrm{V}_0$ ' is the potential at the origin and ' $\mathrm{V}_{\mathrm{A}}$ is the potential at $\mathrm{x}=2 \mathrm{~m}$, then the potential difference $\left(\mathrm{V}_{\mathrm{A}}-\mathrm{V}_0\right)$ is
PhysicsElectrostaticsMHT CETMHT CET 2023 (10 May Shift 2)
Options:
  • A $-80 \mathrm{~J}$
  • B $-120 \mathrm{~J}$
  • C $80 \mathrm{~J}$
  • D $120 \mathrm{~J}$
Solution:
1378 Upvotes Verified Answer
The correct answer is: $-80 \mathrm{~J}$
$\begin{aligned} & d V=\vec{E} \cdot d x \\ & \int_{V_0}^{V_A} d V=-\int_0^2 30 x^2 d x \\ & V_A-V_0=-\left[10 x^3\right]_0^2=-80 J\end{aligned}$

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