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Assuming ideal behaviour, the enthalpy and volume of mixing of two liquids, respectively, are
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The correct answer is:
zero and zero
For Ideal Solution
$\Delta \mathrm{H} \operatorname{Mix}=0 \quad \Delta \mathrm{V} \mathrm{Mix}=0$
$\Delta \mathrm{H} \operatorname{Mix}=0 \quad \Delta \mathrm{V} \mathrm{Mix}=0$
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