Search any question & find its solution
Question:
Answered & Verified by Expert
Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule $\mathrm{B}_2$ is
Options:
Solution:
2503 Upvotes
Verified Answer
The correct answer is:
1 and diamagnetic
1 and diamagnetic
$\mathrm{B}_2$ : Total electrons $=10$
Configuration : $\sigma 1 s^2 \sigma^* 1 s^2 \sigma 2 s^2 \sigma^* 2 s^2 \pi 2 p_x^1=\pi 2 p_y^1$
If Hunds rule is violated, then
$$
\sigma 1 s^2 \sigma^* 1 s^2 \sigma 2 s^2 \sigma^* 2 s^2 \quad \pi 2 p_x^2=\pi 2 p_y^0
$$
So, diamagnetic
$$
\text { Bond order }=\frac{6-4}{2}=1
$$
Chemical bonding
Conceptual
II
Configuration : $\sigma 1 s^2 \sigma^* 1 s^2 \sigma 2 s^2 \sigma^* 2 s^2 \pi 2 p_x^1=\pi 2 p_y^1$
If Hunds rule is violated, then
$$
\sigma 1 s^2 \sigma^* 1 s^2 \sigma 2 s^2 \sigma^* 2 s^2 \quad \pi 2 p_x^2=\pi 2 p_y^0
$$
So, diamagnetic
$$
\text { Bond order }=\frac{6-4}{2}=1
$$
Chemical bonding
Conceptual
II
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.