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Assuming that the junction diode is ideal, the current in the arrangement shown in the circuit diagram is
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Verified Answer
The correct answer is:
\(20 \mathrm{~mA}\)
The circuit diagram is given as
\(\therefore \quad\) Current,
\(\begin{aligned}
I & =\frac{V_A-V_B}{R}=\frac{3-1}{100} \\
& =\frac{2}{100}=0.02 \mathrm{~A}=20 \mathrm{~mA}
\end{aligned}\)
\(\therefore \quad\) Current,
\(\begin{aligned}
I & =\frac{V_A-V_B}{R}=\frac{3-1}{100} \\
& =\frac{2}{100}=0.02 \mathrm{~A}=20 \mathrm{~mA}
\end{aligned}\)
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