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Assuming the balls to be identical except for difference in colours, the number of ways in which one or more balls can be selected from $10$ white, $9$ green and $7$ black balls is
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$879$
$879$
Number of ways of selecting one or more balls from $10$ white, $9$ green, and $7$ black balls $=(10+1)(9+1)(7+1)-1=11 \times 10 \times 8-1=879.$
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