Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Assuming the sun to be a spherical body of radius $\mathrm{R}$ at a temperature of $\mathrm{T} \mathrm{K}$, evaluate the total radiant power, incident on Earth, at a distance $r$ from the Sun.
PhysicsThermal Properties of MatterJEE MainJEE Main 2006
Options:
  • A
    $\frac{\mathrm{R}^2 \sigma \mathrm{T}^4}{\mathrm{r}^2}$
  • B
    $\frac{4 \pi r_0^2 R^2 \sigma T^4}{r^2}$
  • C
    $\frac{\pi r_0^2 R^2 \sigma T^4}{r^2}$
  • D
    $\frac{r_0^2 R^2 \sigma T^4}{4 \pi r^2}$
Solution:
1853 Upvotes Verified Answer
The correct answer is:
$\frac{\pi r_0^2 R^2 \sigma T^4}{r^2}$
$\frac{\pi r_0^2}{4 \pi r^2}\left(\sigma \mathrm{T}^4 \cdot 4 \pi \mathrm{R}^2\right)=\frac{\sigma \pi \mathrm{T}^4 \mathrm{R}^2 \mathrm{r}_0^2}{\mathrm{r}^2}$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.