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At $0^{\circ} \mathrm{C}$ a gas occupies 22.4 liters. What is the temperature in Kelvin to reach the volume of 224 liters?
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The correct answer is:
$2730K$
According to Charles' law, $\frac{\mathrm{V}_1}{\mathrm{~T}_1}=\frac{\mathrm{V}_2}{\mathrm{~T}_2} \quad$ (at constant $\mathrm{n}$ and $\mathrm{P}$ )
$\therefore \quad \mathrm{T}_2=\frac{\mathrm{V}_2 \times \mathrm{T}_1}{\mathrm{~V}_1}=\frac{224 \times 273}{22.4}=2730 \mathrm{~K}$
$\therefore \quad \mathrm{T}_2=\frac{\mathrm{V}_2 \times \mathrm{T}_1}{\mathrm{~V}_1}=\frac{224 \times 273}{22.4}=2730 \mathrm{~K}$
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