At 25 ° C the p H of a 10 – 8 M H C l solution in water is

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Question: Answered & Verified by Expert

At

25 ° C

the

p H

of a

10^{- 8} (M) H C l

solution in water is

ChemistryIonic EquilibriumJEE Main

Options:

A 8
B $- 8$
C between 7 and 8
D between 6 and 7

Solution:

2031 Upvotes Verified Answer

The correct answer is: between 6 and 7

p H

of

10^{- 8} (M) H C l

will be lesser than 7 as it is acidic solution.

[H^{+}] = {[H^{+}]}_{HCl} + {[H^{+}]}_{H_{2} O}

[H^{+}] = 10^{- 8} + 10^{- 7}

∴ [H^{+}] = 1.1 \times 10^{- 7}

pH = 6 .96

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