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Question: Answered & Verified by Expert
At 27°C, a solution containing 2.5 g of solute in 250.0 mL of solution exerts an osmotic pressure of 400 Pa. The molar mass of the solute is g mol-1 (Nearest integer)
(Given : R=0.083 L bar  -1mol-1 )
ChemistrySolutionsJEE MainJEE Main 2023 (31 Jan Shift 1)
Solution:
1104 Upvotes Verified Answer
The correct answer is: 62250

The osmotic pressure of a non-electrolytic solution can be calculated as follows,

π=CRT

π = osmotic pressure

C = molarity

400 Pa105=2.5 gMo250/1000 L×0.83L-barK.mol×300 K

 400 × 10-5(1.01325) = 2.5 × 1000Mo × 250 0.083 × 300

 400 × 10-5 = 10Mo × 0.083 × 300

 Mo = 10 × 0.83 × 300400 × 105

 Mo = 10 × 0.083 × 34 × 105

 Mo=62250 gram/mole

 

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