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At \(293 \mathrm{~K}\), if one starts with \(1.00 \mathrm{~mol}\) of acetic acid and \(0.18 \mathrm{~mol}\) of ethanol, there is 0.171 mol of ethyl acetate in the final equilibrium mixture. Calculate the equilibrium constant.
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Verified Answer
The correct answer is:
$K_c=0.171$
Correct Option is : (B)
$K_c=0.171$
$K_c=0.171$
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