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Question: Answered & Verified by Expert
At \(293 \mathrm{~K}\), if one starts with \(1.00 \mathrm{~mol}\) of acetic acid and \(0.18 \mathrm{~mol}\) of ethanol, there is 0.171 mol of ethyl acetate in the final equilibrium mixture. Calculate the equilibrium constant.
ChemistryIonic EquilibriumNEET
Options:
  • A $K_c=0.157$
  • B $K_c=0.171$
  • C $K_c=1.000$
  • D $K_c=1.156$
Solution:
2042 Upvotes Verified Answer
The correct answer is: $K_c=0.171$
Correct Option is : (B)
$K_c=0.171$

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