At 298 . 2 K the relationship between enthalpy of bond dissociation (in kJ mol - 1 ) for hydrogen E H and its isotope, deuterium E D , is best described by:

Question

At 298 . 2 K the relationship between enthalpy of bond dissociation (in kJ mol - 1 ) for hydrogen E H and its isotope, deuterium E D , is best described by:, E H = 1 2 E D, E H = E D, E H = E D - 7 . 5, E H = 2 E D

MARKS App · Accepted Answer

Enthalpy of bond dissociation kJ / mole at 298 . 2 K For, hydrogen = 435 . 88 For, Deuterium = 443 . 35 ∴ E H ≃ E D - 7 . 5

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