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At \(300 \mathrm{~K}, 36 \mathrm{~g}\) of glucose present in a litre of its solution has an 0 smotic pressure of \(4.98\) bar. If the osmotic pressure of the solution is \(1 \cdot 52\) bars at the same temperature, what would be its concentration?
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\(\pi=C R T\)
\(\begin{aligned} 4.98 &=\frac{W_1}{M_1} \times R \times 300 \\ 4.98 &=\frac{36}{180} \times R \times 300 \\ 4.98 &=60 R \\ \text { In second case } & 1.52=C \times R \times 300 \end{aligned}\)
Diving equation (ii) by equation \((i)\), we get
\(C=\frac{60 \times 1.52}{300 \times 4.98}=0.06 \mathrm{M}\)
\(\begin{aligned} 4.98 &=\frac{W_1}{M_1} \times R \times 300 \\ 4.98 &=\frac{36}{180} \times R \times 300 \\ 4.98 &=60 R \\ \text { In second case } & 1.52=C \times R \times 300 \end{aligned}\)
Diving equation (ii) by equation \((i)\), we get
\(C=\frac{60 \times 1.52}{300 \times 4.98}=0.06 \mathrm{M}\)
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