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Question: Answered & Verified by Expert
At 800°C, the following equilibrium is established as
F 2 g 2 F g
The composition of equilibrium may be determined by measuring the rate of effusion of the mixture through a pin hole. It is found that 800°C and 1 atm mixture effuses 1.6 times as fast as SO2 effuses under the similar conditions. (At. wt. of F=19). What is the value of Kp (in atm) ?
ChemistryChemical EquilibriumJEE Main
Options:
  • A 0.315
  • B 0.685
  • C 0.46
  • D 1.49
Solution:
2322 Upvotes Verified Answer
The correct answer is: 1.49
According to Graham's law of effusion
r  1M

r mix r SO 2 = M SO 2 M mix

⇒   2.56 = 6 4 M mix

⇒   M mixture = 2 5

Let mole fraction of F2 is x. Therefore, mole fraction of F will be 1x

2 5 = 3 8 × x + 1 - x × 1 9 1

x = 0.315 ;

⇒   K p = P F 2 P F 2 = 0.685P 2 0.315P 1.49 atm

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