At 90 ° C , pure water has [ H 3 O + ] = 1 0 - 6 mol l i t r e - 1 . What is the value of K w at 90 ° C?

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Question: Answered & Verified by Expert

At

90 ° C

, pure water has

[H_{3} O^{+}] = 1 0^{- 6}

mol

l i t r e^{- 1}

. What is the value of

K_{w}

at

90 °

C?

ChemistryIonic EquilibriumNEET

Options:

A $1 0^{- 6}$
B $1 0^{- 12}$
C $1 0^{- 14}$
D $1 0^{- 8}$

Solution:

1504 Upvotes Verified Answer

The correct answer is:

1 0^{- 12}

At

90^{o} C, [H_{3} O^{+}]=[{OH}^{-}]

= 10^{- 6} M

So

K_{w} = [H_{3} O^{+}] [O H^{-}]

= 10^{- 6} \times 10^{- 6}

= 10^{- 12}

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