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At a constant pressure $P$, the plot of volume $(V)$ as a function of temperature $(T)$ for 2 moles of an ideal gas gives a straight line with a slope $0.328 \mathrm{~L} \mathrm{~K}^{-1}$. The value of $\mathrm{P}$ (in atm) is closest to [Gas constant, $\mathrm{R}=0.0821 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$ ]
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The correct answer is:
$0.5$
$P V=n R T$
$\Rightarrow \frac{V}{T}=\frac{n R}{P}=$ slope
$\Rightarrow P=\frac{n R}{\text { slope }}=\frac{2 \times 0.0821}{0.328}=0.5$
$\Rightarrow \frac{V}{T}=\frac{n R}{P}=$ slope
$\Rightarrow P=\frac{n R}{\text { slope }}=\frac{2 \times 0.0821}{0.328}=0.5$
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