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At a given point of time the value of displacement of a simple harmonic oscillator is given as y=A cos30°. If amplitude is 40 cm and kinetic energy at that time is 200 J, the value of force constant 1.0×10x N m1. The value of x is _____.

PhysicsOscillationsJEE MainJEE Main 2023 (13 Apr Shift 1)
Solution:
1383 Upvotes Verified Answer
The correct answer is: 4

The formula to calculate the kinetic energy K of a particle executing SHM is given by

K=12kA2-y2   ...1

Substitute the values of the known parameters into equation (1) and solve to calculate the value of the unknown parameter.

K=12×k×A2-A2cos230°= 12×k×A2sin230°200=12×1.0×10x×0.42×122= 2×10x100102=10x-2x-2=2x=4

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