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At a particular locus, the frequency of 'A' allele is 0.6 and that of 'a' is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium?
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The correct answer is:
0.48
The mathematical expression to calculate allele frequency can be given as p + q = 1. Where p represents the frequency of dominant allele and q represents the frequency of recessive allele. The bionomial expression of Hardy Weinberg's law to calculate genotype frequency is p2 + 2pq + q2 = 1
where p2 = homozygoys dominant
2pq = heterozygous dominant
q2 = homozygous recessive.
Frequency of heterozygous individuals
= 2 × 0.6 × 0.4 = 0.48.
where p2 = homozygoys dominant
2pq = heterozygous dominant
q2 = homozygous recessive.
Frequency of heterozygous individuals
= 2 × 0.6 × 0.4 = 0.48.
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