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At constant volume the specific heat of a gas is $\frac{3 R}{2}$, then the value of ' $\gamma$ ' will be
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$\frac{5}{3}$
$C_V=\frac{R}{(\gamma-1)} \Rightarrow$ $\gamma=1+\frac{R}{C_V}=1+\frac{R}{\frac{3}{2} R}=\frac{5}{3}$
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