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At higher temperature, iodoform reaction is given by
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Verified Answer
The correct answer is:
$\mathrm{CH}_3 \mathrm{CO}_2 \mathrm{C}_2 \mathrm{H}_5$
Only $\mathrm{CH}_3 \mathrm{COOC}_2 \mathrm{H}_5$ will give ethanol, $\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}$ after hydrolysis (which can give positive iodoform test).
$$
\begin{aligned}
& \mathrm{CH}_3 \mathrm{COOCH}_3 \rightarrow \mathrm{CH}_3 \mathrm{COOH}+\mathrm{CH}_3 \mathrm{OH} \\
& \mathrm{CH}_3 \mathrm{COOC}_2 \mathrm{H}_5 \rightarrow \mathrm{CH}_3 \mathrm{COOH}+\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH} \\
& \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOCH}_3 \rightarrow \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}+\mathrm{CH}_3 \mathrm{OH} \\
& \mathrm{CH}_3 \mathrm{COOC}_6 \mathrm{H}_5 \rightarrow \mathrm{CH}_3 \mathrm{COOH}+\mathrm{C}_6 \mathrm{H}_5 \mathrm{OH}
\end{aligned}
$$
$$
\begin{aligned}
& \mathrm{CH}_3 \mathrm{COOCH}_3 \rightarrow \mathrm{CH}_3 \mathrm{COOH}+\mathrm{CH}_3 \mathrm{OH} \\
& \mathrm{CH}_3 \mathrm{COOC}_2 \mathrm{H}_5 \rightarrow \mathrm{CH}_3 \mathrm{COOH}+\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH} \\
& \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOCH}_3 \rightarrow \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}+\mathrm{CH}_3 \mathrm{OH} \\
& \mathrm{CH}_3 \mathrm{COOC}_6 \mathrm{H}_5 \rightarrow \mathrm{CH}_3 \mathrm{COOH}+\mathrm{C}_6 \mathrm{H}_5 \mathrm{OH}
\end{aligned}
$$
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