At p H = 2 , E Q u i n h y d r o n e 0 = 1 · 30 V , E Q u i n h y d r o n e will be

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At

p H = 2, E_{Q u i n h y d r o n e}^{0} = 1 \cdot 30 V, E_{Q u i n h y d r o n e}

will be

ChemistryElectrochemistryJEE Main

Options:

A $1 \cdot 36 V$
B $1 \cdot 32 V$
C $1 \cdot 42 V$
D $1 \cdot 26 V$

Solution:

1550 Upvotes Verified Answer

The correct answer is:

1 \cdot 42 V

E = E^{0} - \frac{0.059}{2} l o g {[H^{+}]}^{2} = 1 \cdot 30 - \frac{0.059}{2} l o g {(10^{- 2})}^{2}

= 1 \cdot 30 + \frac{0.236}{2} = 1 \cdot 418 V

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