Search any question & find its solution
Question:
Answered & Verified by Expert
At room temperature, copper has free electron density of $8.4 \times 10^{28} \mathrm{~m}^{-3}$. The electron drift velocity in a copper conductor of cross-sectional area of $10^{-6} \mathrm{~m}^2$ and carrying a current of 5.4 A , will be
Options:
Solution:
1047 Upvotes
Verified Answer
The correct answer is:
$0.4 \mathrm{~mm} \mathrm{~s}^{-1}$
Drift velocity in a copper conductor
$\begin{aligned}
v_d=\frac{i}{n e A} & =\frac{5.4}{8.4 \times 10^{28} \times 1.6 \times 10^{-19} \times 10^{-6}} \\
& =0.4 \times 10^{-3} \mathrm{~ms}^{-1} \\
& =0.4 \mathrm{mms}^{-1}
\end{aligned}$
$\begin{aligned}
v_d=\frac{i}{n e A} & =\frac{5.4}{8.4 \times 10^{28} \times 1.6 \times 10^{-19} \times 10^{-6}} \\
& =0.4 \times 10^{-3} \mathrm{~ms}^{-1} \\
& =0.4 \mathrm{mms}^{-1}
\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.