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At room temperature the average seed of Helium is higher than that of Oxygen by a factor of
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Verified Answer
The correct answer is:
$2 \sqrt{2}$
average speed $\alpha \frac{1}{\sqrt{M}}$
$\begin{array}{l}
\frac{V_{H e}}{V_{O_{2}}}=\sqrt{\frac{32}{4}}=\sqrt{\frac{M_{\mathrm{O}_{2}}}{M_{\text {He }}}} \\
=\sqrt{8}=2 \sqrt{2}
\end{array}$
$\begin{array}{l}
\frac{V_{H e}}{V_{O_{2}}}=\sqrt{\frac{32}{4}}=\sqrt{\frac{M_{\mathrm{O}_{2}}}{M_{\text {He }}}} \\
=\sqrt{8}=2 \sqrt{2}
\end{array}$
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