At STP, 0.48 g of O 2 diffused through a porous partition in 1200 seconds. What volume of CO 2 will diffuse in the same time and under the same conditions ?

Question

At STP, 0.48 g of O 2 diffused through a porous partition in 1200 seconds. What volume of CO 2 will diffuse in the same time and under the same conditions ?, 286.5 mL, 346.7 mL, 112.2 mL, 224.8 mL

MARKS App · Accepted Answer

r 1 r 2 = V 1 / t V 2 / t = V 1 V 2 = M 2 M 1 Volume of 0.48 g of O 2 at STP = 2 2 4 0 0 3 2 × 0 . 4 8 mL (32 g of O 2 occupies 22400 mL at STP) ∴ V O 2 V CO 2 = M CO 2 M O 2 = 4 4 3 2 = 1 . 1 7 3 V CO 2 = V O 2 1 . 1 7 3 = 2 2 4 0 0 3 2 × 0 . 4 8 1 . 1 7 3 = 2 8 6 . 5 mL.

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