At STP, 2.8 litres of hydrogen sulphide were mixed with 1.6 litres of sulphur dioxide and the reaction occurred according to the equation 2 H 2 S g + S O 2 g → 2 H 2 O l + 3 S s Which of the following shows the volume of the gas remaining after the reaction?

Question

At STP, 2.8 litres of hydrogen sulphide were mixed with 1.6 litres of sulphur dioxide and the reaction occurred according to the equation 2 H 2 S g + S O 2 g → 2 H 2 O l + 3 S s Which of the following shows the volume of the gas remaining after the reaction?, 0.2 litres of S O 2 g, 0.4 litres of H 2 g, 1.2 litres of H 2 S g, 1.2 litres of S O 2 g

MARKS App · Accepted Answer

So, Sol 2 vol H 2 S ≡ 1 vol SO 2 or 2 .8 L H 2 S = 1 .4 L SO 2 Hence, after reaction, volume of remaining S O 2 = 1.6 − 1.4 L = 0.2 L

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