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At $T(K)$ and pressure $P$, the diffusion rate of an ideal gas is $120 \mathrm{~mL} \mathrm{~min}^{-1}$. What is the time taken (in sec.) for $3000 \mathrm{~mL}$ of this gas for diffusion at same temperature and pressure?
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$1500$
Diffusion rate $=120 \mathrm{~mL}$ in one minute.
$\Rightarrow$ Time required for the diffusion of $3000 \mathrm{~mL}$ will be :-
$\mathrm{t}=\frac{3000}{120}=25 \text { minutes }=25 \times 60=1500 \text { seconds. }$
$\Rightarrow$ Time required for the diffusion of $3000 \mathrm{~mL}$ will be :-
$\mathrm{t}=\frac{3000}{120}=25 \text { minutes }=25 \times 60=1500 \text { seconds. }$
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