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Question: Answered & Verified by Expert
At $\mathrm{T}(\mathrm{K})$, the molar conductivity of $0.04 \mathrm{M}$ acetic acid is $7.8 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$. If the limiting molar conductivities of $\mathrm{H}^{+}$and $\mathrm{CH}_3 \mathrm{COO}^{-}$at $\mathrm{T}(\mathrm{K})$ are 349 and $41 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$ respectively, the dissociation constant of acetic acid is
ChemistryElectrochemistryAP EAMCETAP EAMCET 2018 (24 Apr Shift 2)
Options:
  • A $1.63 \times 10^{-5}$
  • B $8.33 \times 10^{-5}$
  • C $1.63 \times 10^{-4}$
  • D $8.33 \times 10^{-4}$
Solution:
2539 Upvotes Verified Answer
The correct answer is: $1.63 \times 10^{-5}$
No solution. Refer to answer key.

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