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At the equilibrium position in the process of adsorption
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Verified Answer
The correct answer is:
$\Delta \mathrm{H}=\mathrm{T} \Delta \mathrm{S}$
$\Delta \mathrm{H}=\mathrm{T} \Delta \mathrm{S}$
Equilibrium
$$
\begin{aligned}
&\Delta \mathrm{G}=0 \\
&\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}=0 \\
&\Delta \mathrm{H}=\mathrm{T} \Delta \mathrm{S}
\end{aligned}
$$
$$
\begin{aligned}
&\Delta \mathrm{G}=0 \\
&\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}=0 \\
&\Delta \mathrm{H}=\mathrm{T} \Delta \mathrm{S}
\end{aligned}
$$
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