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Question: Answered & Verified by Expert
At the instant t=0, a force F=kt ( k is a constant) acts on a small body of mass m resting on a smooth horizontal surface. The time, when the body leaves the surface is

PhysicsLaws of MotionJEE Main
Options:
  • A mgksinα
  • B k sin αmg
  • C mg sinαk
  • D mgk sinα
Solution:
2907 Upvotes Verified Answer
The correct answer is: mgk sinα
N+F sinα=mg

The body leaves the surface when the normal reaction on it becomes zero.

N=0 

kt sinα=mg

t=mgksinα

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